Nuprl Lemma : equal_functionality_wrt_subtype_rel2

[A,B:Type]. ∀[x,y:A].  {(x y ∈ A)  (x y ∈ B)} supposing A ⊆B


Proof




Definitions occuring in Statement :  uimplies: supposing a subtype_rel: A ⊆B uall: [x:A]. B[x] guard: {T} implies:  Q universe: Type equal: t ∈ T
Definitions unfolded in proof :  guard: {T} uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a implies:  Q subtype_rel: A ⊆B prop:
Lemmas referenced :  equal_wf subtype_rel_wf
Rules used in proof :  sqequalSubstitution sqequalRule sqequalReflexivity sqequalTransitivity computationStep isect_memberFormation introduction cut lambdaFormation hypothesis applyEquality lambdaEquality hypothesisEquality sqequalHypSubstitution extract_by_obid isectElimination thin cumulativity dependent_functionElimination axiomEquality isect_memberEquality because_Cache equalityTransitivity equalitySymmetry universeEquality

Latex:
\mforall{}[A,B:Type].  \mforall{}[x,y:A].    \{(x  =  y)  {}\mRightarrow{}  (x  =  y)\}  supposing  A  \msubseteq{}r  B



Date html generated: 2017_04_14-AM-07_14_07
Last ObjectModification: 2017_02_27-PM-02_50_00

Theory : subtype_0


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