Nuprl Lemma : bag-map-member-wf

[A,B:Type]. ∀[bs:bag(A)]. ∀[f:{a:A| a ↓∈ bs}  ⟶ B].  (bag-map(f;bs) ∈ bag(B))


Proof




Definitions occuring in Statement :  bag-member: x ↓∈ bs bag-map: bag-map(f;bs) bag: bag(T) uall: [x:A]. B[x] member: t ∈ T set: {x:A| B[x]}  function: x:A ⟶ B[x] universe: Type
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T prop: all: x:A. B[x]
Lemmas referenced :  bag-map_wf bag-member_wf bag-subtype bag_wf
Rules used in proof :  cut lemma_by_obid sqequalHypSubstitution sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isectElimination thin hypothesisEquality setEquality hypothesis cumulativity dependent_functionElimination equalityTransitivity equalitySymmetry functionEquality because_Cache universeEquality isect_memberFormation introduction sqequalRule axiomEquality isect_memberEquality

Latex:
\mforall{}[A,B:Type].  \mforall{}[bs:bag(A)].  \mforall{}[f:\{a:A|  a  \mdownarrow{}\mmember{}  bs\}    {}\mrightarrow{}  B].    (bag-map(f;bs)  \mmember{}  bag(B))



Date html generated: 2016_05_15-PM-02_47_01
Last ObjectModification: 2015_12_27-AM-09_36_29

Theory : bags


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