Nuprl Lemma : has-value_functionality

[a,b:Base].  {(a)↓  (b)↓supposing a ≤ b


Proof




Definitions occuring in Statement :  has-value: (a)↓ uimplies: supposing a uall: [x:A]. B[x] guard: {T} implies:  Q base: Base sqle: s ≤ t
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a guard: {T} implies:  Q has-value: (a)↓ prop: all: x:A. B[x]
Lemmas referenced :  has-value_wf_base sqle_wf_base base_wf sqle_trans cbv-sqequal0 is-exception_wf
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut lambdaFormation sqequalHypSubstitution extract_by_obid isectElimination thin hypothesisEquality hypothesis sqequalRule lambdaEquality dependent_functionElimination axiomSqleEquality isect_memberEquality because_Cache equalityTransitivity equalitySymmetry baseClosed baseApply closedConclusion independent_functionElimination divergentSqle sqleRule independent_isectElimination

Latex:
\mforall{}[a,b:Base].    \{(a)\mdownarrow{}  {}\mRightarrow{}  (b)\mdownarrow{}\}  supposing  a  \mleq{}  b



Date html generated: 2017_02_20-AM-10_54_53
Last ObjectModification: 2017_01_26-PM-00_14_26

Theory : general


Home Index