Nuprl Lemma : oobboth_wf
∀[A,B:Type]. ∀[bval:A × B]. (oobboth(bval) ∈ one_or_both(A;B))
Proof
Definitions occuring in Statement :
oobboth: oobboth(bval),
one_or_both: one_or_both(A;B),
uall: ∀[x:A]. B[x],
member: t ∈ T,
product: x:A × B[x],
universe: Type
Definitions unfolded in proof :
oobboth: oobboth(bval),
one_or_both: one_or_both(A;B),
uall: ∀[x:A]. B[x],
member: t ∈ T
Rules used in proof :
sqequalSubstitution,
sqequalRule,
sqequalReflexivity,
sqequalTransitivity,
computationStep,
isect_memberFormation,
introduction,
cut,
inlEquality,
hypothesisEquality,
unionEquality,
sqequalHypSubstitution,
hypothesis,
axiomEquality,
equalityTransitivity,
equalitySymmetry,
productEquality,
thin,
isect_memberEquality,
isectElimination,
because_Cache,
universeEquality
Latex:
\mforall{}[A,B:Type]. \mforall{}[bval:A \mtimes{} B]. (oobboth(bval) \mmember{} one\_or\_both(A;B))
Date html generated:
2016_05_15-PM-05_31_30
Last ObjectModification:
2015_12_27-PM-02_09_57
Theory : general
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