Nuprl - Proof: finite-partition 2 2 1 1 2

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At: finite-partition 2 2 1 1 2

1. n:
2. 0 < n
3. k:
4. c: nk
5. p: k( List)
6. sum(||p(j)|| | j < k) = n-1
7. j:k, x,y:||p(j)||. x < y (p(j))[x] > (p(j))[y]
8. j:k, x:||p(j)||. (p(j))[x] < n-1 & c((p(j))[x]) = j
9. j: k
10. x,y:||p(j)||. x < y (p(j))[x] > (p(j))[y]
11. c(n-1) = j
12. x@0: (||p(j)||+1)
13. y: (||p(j)||+1)
14. x@0 = 0
15. x@0 < y

(p(j))[(x@0-1)] > (p(j))[(y-1)]

By: EasyHyp'

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(26steps total) PrintForm Definitions Lemmas graph 1 2 Sections Graphs Doc