Nuprl Lemma : empty_support

[n:ℕ]. ∀[f:ℕn ⟶ ℤ].  Σ(f[x] x < n) 0 ∈ ℤ supposing ∀x:ℕn. (f[x] 0 ∈ ℤ)


Proof




Definitions occuring in Statement :  sum: Σ(f[x] x < k) int_seg: {i..j-} nat: uimplies: supposing a uall: [x:A]. B[x] so_apply: x[s] all: x:A. B[x] function: x:A ⟶ B[x] natural_number: $n int: equal: t ∈ T
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a squash: T prop: so_lambda: λ2x.t[x] so_apply: x[s] nat: true: True subtype_rel: A ⊆B guard: {T} iff: ⇐⇒ Q and: P ∧ Q rev_implies:  Q implies:  Q all: x:A. B[x]
Lemmas referenced :  equal_wf squash_wf true_wf istype-universe sum-is-zero int_seg_wf subtype_rel_self iff_weakening_equal istype-int int_subtype_base istype-nat
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity Error :isect_memberFormation_alt,  introduction cut applyEquality thin Error :lambdaEquality_alt,  sqequalHypSubstitution imageElimination extract_by_obid isectElimination hypothesisEquality equalityTransitivity hypothesis equalitySymmetry Error :universeIsType,  Error :inhabitedIsType,  instantiate universeEquality intEquality sqequalRule natural_numberEquality setElimination rename independent_isectElimination imageMemberEquality baseClosed because_Cache productElimination independent_functionElimination Error :functionIsType,  Error :equalityIsType4,  Error :isect_memberEquality_alt,  axiomEquality Error :isectIsTypeImplies

Latex:
\mforall{}[n:\mBbbN{}].  \mforall{}[f:\mBbbN{}n  {}\mrightarrow{}  \mBbbZ{}].    \mSigma{}(f[x]  |  x  <  n)  =  0  supposing  \mforall{}x:\mBbbN{}n.  (f[x]  =  0)



Date html generated: 2019_06_20-PM-01_18_27
Last ObjectModification: 2018_10_18-PM-00_43_37

Theory : int_2


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