Nuprl Lemma : filter_is_nil2

[T:Type]. ∀[L:T List]. ∀[P:{x:T| (x ∈ L)}  ⟶ 𝔹].  filter(P;L) [] supposing (∀x∈L.¬↑P[x])


Proof




Definitions occuring in Statement :  l_all: (∀x∈L.P[x]) l_member: (x ∈ l) filter: filter(P;l) nil: [] list: List assert: b bool: 𝔹 uimplies: supposing a uall: [x:A]. B[x] so_apply: x[s] not: ¬A set: {x:A| B[x]}  function: x:A ⟶ B[x] universe: Type sqequal: t
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a prop: so_apply: x[s] so_lambda: λ2x.t[x]
Lemmas referenced :  filter_is_nil l_member_wf list-subtype l_all_wf not_wf assert_wf bool_wf list_wf
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut lemma_by_obid sqequalHypSubstitution isectElimination thin setEquality hypothesisEquality hypothesis cumulativity equalityTransitivity equalitySymmetry independent_isectElimination sqequalRule sqequalAxiom lambdaEquality applyEquality isect_memberEquality because_Cache functionEquality universeEquality

Latex:
\mforall{}[T:Type].  \mforall{}[L:T  List].  \mforall{}[P:\{x:T|  (x  \mmember{}  L)\}    {}\mrightarrow{}  \mBbbB{}].    filter(P;L)  \msim{}  []  supposing  (\mforall{}x\mmember{}L.\mneg{}\muparrow{}P[x])



Date html generated: 2016_05_14-AM-06_51_28
Last ObjectModification: 2015_12_26-PM-00_22_06

Theory : list_0


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