Nuprl Lemma : strong-continuity2_biject

∀[T,S:Type].
  ∀g:S ⟶ ℕ
    (Bij(S;ℕ;g)
    ⇒ (∀F:(ℕ ⟶ T) ⟶ S
          (strong-continuity2(T;g o F)
          ⇒ (∃M:n:ℕ ⟶ (ℕn ⟶ T) ⟶ (S?)
               ∀f:ℕ ⟶ T
                 ((∃n:ℕ. ((M n f) = (inl (F f)) ∈ (S?)))
                 ∧ (∀n:ℕ. (M n f) = (inl (F f)) ∈ (S?) supposing ↑isl(M n f)))))))


Proof




Definitions occuring in Statement :  strong-continuity2: strong-continuity2(T;F),  biject: Bij(A;B;f),  compose: f o g,  int_seg: {i..j-},  nat: ℕ,  assert: ↑b,  isl: isl(x),  uimplies: b supposing a,  uall: ∀[x:A]. B[x],  all: ∀x:A. B[x],  exists: ∃x:A. B[x],  implies: P ⇒ Q,  and: P ∧ Q,  unit: Unit,  apply: f a,  function: x:A ⟶ B[x],  inl: inl x,  union: left + right,  natural_number: $n,  universe: Type,  equal: s = t ∈ T
Definitions unfolded in proof :  prop: ℙ,  nat: ℕ,  implies: P ⇒ Q,  all: ∀x:A. B[x],  member: t ∈ T,  uall: ∀[x:A]. B[x]
Lemmas referenced :  le_wf,  zero-le-nat,  subtype_rel_self,  nat_wf,  strong-continuity2_biject_retract
Rules used in proof :  universeEquality,  rename,  setElimination,  sqequalRule,  dependent_set_memberEquality,  applyEquality,  lambdaFormation,  because_Cache,  independent_functionElimination,  lambdaEquality,  dependent_functionElimination,  hypothesisEquality,  thin,  isectElimination,  sqequalHypSubstitution,  hypothesis,  isect_memberFormation,  sqequalReflexivity,  computationStep,  sqequalTransitivity,  sqequalSubstitution,  extract_by_obid,  introduction,  cut

Latex:
\mforall{}[T,S:Type].
    \mforall{}g:S  {}\mrightarrow{}  \mBbbN{}
        (Bij(S;\mBbbN{};g)
        {}\mRightarrow{}  (\mforall{}F:(\mBbbN{}  {}\mrightarrow{}  T)  {}\mrightarrow{}  S
                    (strong-continuity2(T;g  o  F)
                    {}\mRightarrow{}  (\mexists{}M:n:\mBbbN{}  {}\mrightarrow{}  (\mBbbN{}n  {}\mrightarrow{}  T)  {}\mrightarrow{}  (S?)
                              \mforall{}f:\mBbbN{}  {}\mrightarrow{}  T
                                  ((\mexists{}n:\mBbbN{}.  ((M  n  f)  =  (inl  (F  f))))
                                  \mwedge{}  (\mforall{}n:\mBbbN{}.  (M  n  f)  =  (inl  (F  f))  supposing  \muparrow{}isl(M  n  f)))))))



Date html generated: 2017_09_29-PM-06_05_19
Last ObjectModification: 2017_09_04-AM-10_36_13

Theory : continuity


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