Nuprl Lemma : member-per-or-left

[A,B:Type]. ∀[a:A].  (<Ax, a> ∈ per-or(A;B))


Proof




Definitions occuring in Statement :  per-or: per-or(A;B) uall: [x:A]. B[x] member: t ∈ T pair: <a, b> universe: Type axiom: Ax
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T per-or: per-or(A;B) per-exists: per-exists(A;a.B[a]) so_lambda: λ2x.t[x] so_apply: x[s] per-or-family: per-or-family(A;B) has-value: (a)↓ uimplies: supposing a
Lemmas referenced :  member-per-product per-value_wf per-or-family_wf member-per-value has-value_wf_base is-exception_wf
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut extract_by_obid sqequalHypSubstitution isectElimination thin hypothesis sqequalRule hypothesisEquality axiomEquality equalityTransitivity equalitySymmetry isect_memberEquality because_Cache universeEquality sqleReflexivity divergentSqle independent_isectElimination baseClosed lemma_by_obid

Latex:
\mforall{}[A,B:Type].  \mforall{}[a:A].    (<Ax,  a>  \mmember{}  per-or(A;B))



Date html generated: 2019_06_20-AM-11_30_36
Last ObjectModification: 2018_08_22-PM-02_05_47

Theory : per!type


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