Nuprl Lemma : Prime-isOdd

p:Prime. ((¬(p 2 ∈ ℤ))  (↑isOdd(p)))


Proof




Definitions occuring in Statement :  Prime: Prime isOdd: isOdd(n) assert: b all: x:A. B[x] not: ¬A implies:  Q natural_number: $n int: equal: t ∈ T
Definitions unfolded in proof :  squash: T prop: not: ¬A false: False less_than': less_than'(a;b) and: P ∧ Q le: A ≤ B nat: subtype_rel: A ⊆B sq_stable: SqStable(P) int_upper: {i...} member: t ∈ T uall: [x:A]. B[x] Prime: Prime implies:  Q all: x:A. B[x]
Lemmas referenced :  Prime_wf equal-wf-T-base not_wf le_wf false_wf int_upper_subtype_nat prime-isOdd isOdd_wf sq_stable__assert
Rules used in proof :  intEquality imageElimination baseClosed imageMemberEquality independent_pairFormation sqequalRule natural_numberEquality dependent_set_memberEquality applyEquality dependent_functionElimination independent_functionElimination hypothesis hypothesisEquality isectElimination extract_by_obid introduction cut rename thin setElimination sqequalHypSubstitution lambdaFormation sqequalReflexivity computationStep sqequalTransitivity sqequalSubstitution

Latex:
\mforall{}p:Prime.  ((\mneg{}(p  =  2))  {}\mRightarrow{}  (\muparrow{}isOdd(p)))



Date html generated: 2018_05_21-PM-06_58_02
Last ObjectModification: 2017_12_31-PM-06_12_35

Theory : general


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