Nuprl Lemma : polyconst_wf

[k,n:ℤ].  (polyconst(k) ∈ polynom(n))


Proof




Definitions occuring in Statement :  polyconst: polyconst(k) polynom: polynom(n) uall: [x:A]. B[x] member: t ∈ T int:
Definitions unfolded in proof :  polynom: polynom(n) uall: [x:A]. B[x] member: t ∈ T polyconst: polyconst(k) implies:  Q assert: b ifthenelse: if then else fi  tree_leaf?: tree_leaf?(v) eq_atom: =a y pi1: fst(t) tree_leaf: tree_leaf(value) btrue: tt true: True prop: ispolyform: ispolyform(p) tree_ind: tree_ind polyform: polyform(n)
Lemmas referenced :  assert_wf poly-int_wf tree_leaf_wf ispolyform_wf tree_leaf?_wf
Rules used in proof :  sqequalSubstitution sqequalRule sqequalReflexivity sqequalTransitivity computationStep isect_memberFormation introduction cut lambdaFormation hypothesis natural_numberEquality extract_by_obid sqequalHypSubstitution isectElimination thin intEquality hypothesisEquality dependent_set_memberEquality applyEquality functionEquality setElimination rename because_Cache axiomEquality equalityTransitivity equalitySymmetry isect_memberEquality

Latex:
\mforall{}[k,n:\mBbbZ{}].    (polyconst(k)  \mmember{}  polynom(n))



Date html generated: 2017_10_01-AM-08_32_22
Last ObjectModification: 2017_05_02-PM-00_39_20

Theory : integer!polynomial!trees


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