Nuprl Lemma : add-add-zero-in-top

[a,b:Top].  ((a b) b)


Proof




Definitions occuring in Statement :  uall: [x:A]. B[x] top: Top add: m natural_number: $n sqequal: t
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T has-value: (a)↓ and: P ∧ Q all: x:A. B[x] implies:  Q uimplies: supposing a prop: false: False
Lemmas referenced :  value-type-has-value int-value-type equal_wf add-zero exception-not-value top_wf
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut sqequalSqle sqleRule thin divergentSqle callbyvalueAdd sqequalHypSubstitution hypothesis sqequalRule baseApply closedConclusion baseClosed hypothesisEquality productElimination equalityTransitivity equalitySymmetry because_Cache lambdaFormation extract_by_obid isectElimination intEquality independent_isectElimination dependent_functionElimination independent_functionElimination sqleReflexivity addExceptionCases axiomSqleEquality natural_numberEquality voidElimination exceptionSqequal addEquality sqequalAxiom isect_memberEquality

Latex:
\mforall{}[a,b:Top].    ((a  +  b)  +  0  \msim{}  a  +  b)



Date html generated: 2017_10_01-AM-08_43_29
Last ObjectModification: 2017_07_26-PM-04_29_48

Theory : untyped!computation


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