Nuprl Lemma : seq-count_wf

[T:Type]. ∀[eq:T ⟶ T ⟶ 𝔹]. ∀[f:ℕ ⟶ T]. ∀[x:T]. ∀[j:ℕ].  (#{i<j|f eq x} ∈ ℕ1)


Proof




Definitions occuring in Statement :  seq-count: #{i<j|f eq x} int_seg: {i..j-} nat: bool: 𝔹 uall: [x:A]. B[x] member: t ∈ T function: x:A ⟶ B[x] add: m natural_number: $n universe: Type
Definitions unfolded in proof :  seq-count: #{i<j|f eq x} uall: [x:A]. B[x] member: t ∈ T nat: subtype_rel: A ⊆B so_lambda: λ2x.t[x] so_apply: x[s] uimplies: supposing a le: A ≤ B and: P ∧ Q less_than': less_than'(a;b) false: False not: ¬A implies:  Q prop: all: x:A. B[x]
Lemmas referenced :  bool-size_wf compose_wf int_seg_wf bool_wf subtype_rel_dep_function nat_wf int_seg_subtype_nat false_wf
Rules used in proof :  sqequalSubstitution sqequalRule sqequalReflexivity sqequalTransitivity computationStep isect_memberFormation introduction cut lemma_by_obid sqequalHypSubstitution isectElimination thin hypothesisEquality natural_numberEquality setElimination rename hypothesis cumulativity applyEquality lambdaEquality independent_isectElimination independent_pairFormation lambdaFormation because_Cache axiomEquality equalityTransitivity equalitySymmetry isect_memberEquality functionEquality universeEquality

Latex:
\mforall{}[T:Type].  \mforall{}[eq:T  {}\mrightarrow{}  T  {}\mrightarrow{}  \mBbbB{}].  \mforall{}[f:\mBbbN{}  {}\mrightarrow{}  T].  \mforall{}[x:T].  \mforall{}[j:\mBbbN{}].    (\#\{i<j|f  i  eq  x\}  \mmember{}  \mBbbN{}j  +  1)



Date html generated: 2016_05_15-PM-04_43_53
Last ObjectModification: 2015_12_27-PM-02_38_57

Theory : general


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