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prime factorization existsLEMMA
1
2
2
1
1
1. k : {2...}
2. n :
3. n1:.
3. n1<n
3.
3. (g:({2..k}).
3. (2 n1 < k+1
3. (
3. ((i:{2..k}. n1i 0<g(i) prime(i))
3. (
3. ((h:({2..k}).
3. (({2..k}(g) = {2..k}(h) & is_prime_factorization(2; k; h)))
4. g : {2..k}
5. 2n
6. n<k+1
7. i:{2..k}. ni 0<g(i) prime(i)
8. n = 2
9. prime(n-1)
10. g' : {2..k}
11. {2..k}(g) = {2..k}(g')
12. g'(n-1) = 0
13. u:{2..k}. n-1<u g'(u) = g(u)
14. i : {2..k}
15. n-1i
16. 0<g'(i)
prime(i)
Generated subgoal:
1 |
0<g(i)
| 1 step |
About:
IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html