Nuprl Lemma : es-interface-left-as-image

[Info,A,B:Type]. ∀[X:EClass(A B)].  (left(X) = λx.case of inl(a) => {a} inr(b) => {}[X] ∈ EClass(A))


Proof




Definitions occuring in Statement :  es-interface-left: left(X) es-filter-image: f[X] eclass: EClass(A[eo; e]) uall: [x:A]. B[x] lambda: λx.A[x] decide: case of inl(x) => s[x] inr(y) => t[y] union: left right universe: Type equal: t ∈ T single-bag: {x} empty-bag: {}
Lemmas :  in-eclass_wf es-interface-subtype_rel2 es-E_wf event-ordering+_subtype top_wf subtype_top bool_wf eqtt_to_assert single-eclass-val eclass-val_wf equal_wf bag_wf bag-separate_wf single-bag_wf empty-bag_wf eqff_to_assert bool_cases_sqequal subtype_base_sq bool_subtype_base assert-bnot eclass_wf event-ordering+_wf filter_cons_lemma filter_nil_lemma map_cons_lemma map_nil_lemma

Latex:
\mforall{}[Info,A,B:Type].  \mforall{}[X:EClass(A  +  B)].    (left(X)  =  \mlambda{}x.case  x  of  inl(a)  =>  \{a\}  |  inr(b)  =>  \{\}[X])



Date html generated: 2015_07_21-PM-03_30_02
Last ObjectModification: 2015_01_27-PM-06_37_40

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