Nuprl Lemma : is-filter-image-sq
∀[Info:Type]. ∀[es:EO+(Info)]. ∀[f:Top]. ∀[X:EClass(Top)]. ∀[e:E]. (e ∈b f[X] ~ e ∈b X ∧b (#(f X(e)) =z 1))
Proof
Definitions occuring in Statement :
es-filter-image: f[X],
eclass-val: X(e),
in-eclass: e ∈b X,
eclass: EClass(A[eo; e]),
event-ordering+: EO+(Info),
es-E: E,
band: p ∧b q,
eq_int: (i =z j),
uall: ∀[x:A]. B[x],
top: Top,
apply: f a,
natural_number: $n,
universe: Type,
sqequal: s ~ t,
bag-size: #(bs)
Lemmas :
eq_int_wf,
bag-size_wf,
bool_wf,
eqtt_to_assert,
assert_of_eq_int,
nat_wf,
eqff_to_assert,
equal_wf,
bool_cases_sqequal,
subtype_base_sq,
bool_subtype_base,
assert-bnot,
neg_assert_of_eq_int,
bag_size_empty_lemma,
es-E_wf,
event-ordering+_subtype,
event-ordering+_wf,
bag_wf,
top_wf
\mforall{}[Info:Type]. \mforall{}[es:EO+(Info)]. \mforall{}[f:Top]. \mforall{}[X:EClass(Top)]. \mforall{}[e:E].
(e \mmember{}\msubb{} f[X] \msim{} e \mmember{}\msubb{} X \mwedge{}\msubb{} (\#(f X(e)) =\msubz{} 1))
Date html generated:
2015_07_17-PM-01_06_14
Last ObjectModification:
2015_01_27-PM-10_35_57
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