Nuprl Lemma : fpf-cap_functionality_wrt_sub

∀[A:Type]. ∀[d1,d2,d3,d4:EqDecider(A)]. ∀[B:A ⟶ Type]. ∀[f,g:a:A fp-> B[a]]. ∀[x:A]. ∀[z:B[x]].
  (f(x)?z = g(x)?z ∈ B[x]) supposing ((↑x ∈ dom(f)) and f ⊆ g)


Proof




Definitions occuring in Statement :  fpf-sub: f ⊆ g,  fpf-cap: f(x)?z,  fpf-dom: x ∈ dom(f),  fpf: a:A fp-> B[a],  deq: EqDecider(T),  assert: ↑b,  uimplies: b supposing a,  uall: ∀[x:A]. B[x],  so_apply: x[s],  function: x:A ⟶ B[x],  universe: Type,  equal: s = t ∈ T
Definitions unfolded in proof :  bfalse: ff,  ifthenelse: if b then t else f fi ,  and: P ∧ Q,  uiff: uiff(P;Q),  btrue: tt,  it: ⋅,  unit: Unit,  bool: 𝔹,  implies: P ⇒ Q,  top: Top,  all: ∀x:A. B[x],  so_apply: x[s],  so_lambda: λ2x.t[x],  subtype_rel: A ⊆r B,  prop: ℙ,  fpf-cap: f(x)?z,  uimplies: b supposing a,  member: t ∈ T,  uall: ∀[x:A]. B[x],  pi2: snd(t),  fpf-ap: f(x),  cand: A c∧ B,  guard: {T},  fpf-sub: f ⊆ g,  false: False,  not: ¬A
Lemmas referenced :  equal_wf,  assert_of_bnot,  eqff_to_assert,  uiff_transitivity,  eqtt_to_assert,  not_wf,  bnot_wf,  equal-wf-T-base,  bool_wf,  deq_wf,  fpf_wf,  fpf-sub_wf,  top_wf,  subtype-fpf2,  fpf-dom_wf,  assert_wf,  fpf-dom_functionality2
Rules used in proof :  dependent_functionElimination,  independent_functionElimination,  productElimination,  equalityElimination,  unionElimination,  baseClosed,  equalitySymmetry,  equalityTransitivity,  axiomEquality,  because_Cache,  voidEquality,  voidElimination,  isect_memberEquality,  lambdaFormation,  independent_isectElimination,  functionExtensionality,  lambdaEquality,  sqequalRule,  applyEquality,  hypothesisEquality,  cumulativity,  thin,  isectElimination,  sqequalHypSubstitution,  extract_by_obid,  hypothesis,  cut,  introduction,  isect_memberFormation,  sqequalReflexivity,  computationStep,  sqequalTransitivity,  sqequalSubstitution,  universeIsType,  Error :memTop,  lambdaFormation_alt,  inhabitedIsType,  lambdaEquality_alt

Latex:
\mforall{}[A:Type].  \mforall{}[d1,d2,d3,d4:EqDecider(A)].  \mforall{}[B:A  {}\mrightarrow{}  Type].  \mforall{}[f,g:a:A  fp->  B[a]].  \mforall{}[x:A].  \mforall{}[z:B[x]].
    (f(x)?z  =  g(x)?z)  supposing  ((\muparrow{}x  \mmember{}  dom(f))  and  f  \msubseteq{}  g)



Date html generated: 2020_05_20-AM-09_02_24
Last ObjectModification: 2020_01_25-AM-11_42_15

Theory : finite!partial!functions


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