Nuprl Lemma : fpf-cap_functionality_wrt_sub
∀[A:Type]. ∀[d1,d2,d3,d4:EqDecider(A)]. ∀[B:A ⟶ Type]. ∀[f,g:a:A fp-> B[a]]. ∀[x:A]. ∀[z:B[x]].
  (f(x)?z = g(x)?z ∈ B[x]) supposing ((↑x ∈ dom(f)) and f ⊆ g)
Proof
Definitions occuring in Statement : 
fpf-sub: f ⊆ g
, 
fpf-cap: f(x)?z
, 
fpf-dom: x ∈ dom(f)
, 
fpf: a:A fp-> B[a]
, 
deq: EqDecider(T)
, 
assert: ↑b
, 
uimplies: b supposing a
, 
uall: ∀[x:A]. B[x]
, 
so_apply: x[s]
, 
function: x:A ⟶ B[x]
, 
universe: Type
, 
equal: s = t ∈ T
Definitions unfolded in proof : 
bfalse: ff
, 
ifthenelse: if b then t else f fi 
, 
and: P ∧ Q
, 
uiff: uiff(P;Q)
, 
btrue: tt
, 
it: ⋅
, 
unit: Unit
, 
bool: 𝔹
, 
implies: P 
⇒ Q
, 
top: Top
, 
all: ∀x:A. B[x]
, 
so_apply: x[s]
, 
so_lambda: λ2x.t[x]
, 
subtype_rel: A ⊆r B
, 
prop: ℙ
, 
fpf-cap: f(x)?z
, 
uimplies: b supposing a
, 
member: t ∈ T
, 
uall: ∀[x:A]. B[x]
, 
pi2: snd(t)
, 
fpf-ap: f(x)
, 
cand: A c∧ B
, 
guard: {T}
, 
fpf-sub: f ⊆ g
, 
false: False
, 
not: ¬A
Lemmas referenced : 
equal_wf, 
assert_of_bnot, 
eqff_to_assert, 
uiff_transitivity, 
eqtt_to_assert, 
not_wf, 
bnot_wf, 
equal-wf-T-base, 
bool_wf, 
deq_wf, 
fpf_wf, 
fpf-sub_wf, 
top_wf, 
subtype-fpf2, 
fpf-dom_wf, 
assert_wf, 
fpf-dom_functionality2
Rules used in proof : 
dependent_functionElimination, 
independent_functionElimination, 
productElimination, 
equalityElimination, 
unionElimination, 
baseClosed, 
equalitySymmetry, 
equalityTransitivity, 
axiomEquality, 
because_Cache, 
voidEquality, 
voidElimination, 
isect_memberEquality, 
lambdaFormation, 
independent_isectElimination, 
functionExtensionality, 
lambdaEquality, 
sqequalRule, 
applyEquality, 
hypothesisEquality, 
cumulativity, 
thin, 
isectElimination, 
sqequalHypSubstitution, 
extract_by_obid, 
hypothesis, 
cut, 
introduction, 
isect_memberFormation, 
sqequalReflexivity, 
computationStep, 
sqequalTransitivity, 
sqequalSubstitution, 
universeIsType, 
Error :memTop, 
lambdaFormation_alt, 
inhabitedIsType, 
lambdaEquality_alt
Latex:
\mforall{}[A:Type].  \mforall{}[d1,d2,d3,d4:EqDecider(A)].  \mforall{}[B:A  {}\mrightarrow{}  Type].  \mforall{}[f,g:a:A  fp->  B[a]].  \mforall{}[x:A].  \mforall{}[z:B[x]].
    (f(x)?z  =  g(x)?z)  supposing  ((\muparrow{}x  \mmember{}  dom(f))  and  f  \msubseteq{}  g)
Date html generated:
2020_05_20-AM-09_02_24
Last ObjectModification:
2020_01_25-AM-11_42_15
Theory : finite!partial!functions
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