Nuprl Lemma : es-is-filter-image

[Info:Type]. ∀[es:EO+(Info)]. ∀[A,B:Type]. ∀[f:A ─→ bag(B)]. ∀[X:EClass(A)]. ∀[e:E].
  uiff(↑e ∈b f[X];(↑e ∈b X) ∧ (#(f X(e)) 1 ∈ ℤ))


Proof




Definitions occuring in Statement :  es-filter-image: f[X] eclass-val: X(e) in-eclass: e ∈b X eclass: EClass(A[eo; e]) event-ordering+: EO+(Info) es-E: E assert: b uiff: uiff(P;Q) uall: [x:A]. B[x] and: P ∧ Q apply: a function: x:A ─→ B[x] natural_number: $n int: universe: Type equal: t ∈ T bag-size: #(bs) bag: bag(T)
Lemmas :  is-filter-image-sq es-interface-subtype_rel2 es-E_wf event-ordering+_subtype top_wf in-eclass_wf bool_wf eqtt_to_assert assert_of_eq_int bag-size_wf eclass-val_wf assert_wf eq_int_wf assert_witness true_wf equal-wf-T-base eqff_to_assert equal_wf bool_cases_sqequal subtype_base_sq bool_subtype_base assert-bnot false_wf event-ordering+_wf es-filter-image_wf subtype_rel_dep_function bag_wf subtype_rel_bag nat_wf eclass_wf
\mforall{}[Info:Type].  \mforall{}[es:EO+(Info)].  \mforall{}[A,B:Type].  \mforall{}[f:A  {}\mrightarrow{}  bag(B)].  \mforall{}[X:EClass(A)].  \mforall{}[e:E].
    uiff(\muparrow{}e  \mmember{}\msubb{}  f[X];(\muparrow{}e  \mmember{}\msubb{}  X)  \mwedge{}  (\#(f  X(e))  =  1))



Date html generated: 2015_07_17-PM-01_06_30
Last ObjectModification: 2015_01_27-PM-10_35_45

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