Nuprl Lemma : fpf-sub-join-right2

[A:Type]. ∀[B,C:A ⟶ Type]. ∀[eq:EqDecider(A)]. ∀[f:a:A fp-> B[a]]. ∀[g:a:A fp-> C[a]].
  g ⊆ f ⊕ supposing ∀x:A. (((↑x ∈ dom(f)) ∧ (↑x ∈ dom(g)))  ((B[x] ⊆C[x]) c∧ (f(x) g(x) ∈ C[x])))


Proof




Definitions occuring in Statement :  fpf-join: f ⊕ g fpf-sub: f ⊆ g fpf-ap: f(x) fpf-dom: x ∈ dom(f) fpf: a:A fp-> B[a] deq: EqDecider(T) assert: b uimplies: supposing a subtype_rel: A ⊆B uall: [x:A]. B[x] cand: c∧ B so_apply: x[s] all: x:A. B[x] implies:  Q and: P ∧ Q function: x:A ⟶ B[x] universe: Type equal: t ∈ T
Definitions unfolded in proof :  fpf-sub: f ⊆ g uall: [x:A]. B[x] uimplies: supposing a member: t ∈ T all: x:A. B[x] implies:  Q cand: c∧ B so_lambda: λ2x.t[x] so_apply: x[s] subtype_rel: A ⊆B and: P ∧ Q respects-equality: respects-equality(S;T) iff: ⇐⇒ Q rev_implies:  Q or: P ∨ Q fpf-join: f ⊕ g fpf-ap: f(x) pi2: snd(t) fpf-cap: f(x)?z bool: 𝔹 unit: Unit it: btrue: tt uiff: uiff(P;Q) ifthenelse: if then else fi  bfalse: ff
Lemmas referenced :  assert_witness fpf-dom_wf fpf-join_wf top_wf subtype-fpf2 istype-assert subtype_rel_wf fpf-ap_wf subtype-respects-equality fpf_wf deq_wf istype-universe fpf-join-dom2 equal-wf-T-base bool_wf assert_wf bnot_wf not_wf eqtt_to_assert uiff_transitivity eqff_to_assert assert_of_bnot trivial-equal
Rules used in proof :  sqequalSubstitution sqequalRule sqequalReflexivity sqequalTransitivity computationStep isect_memberFormation_alt introduction cut thin lambdaFormation_alt independent_pairFormation hypothesis because_Cache sqequalHypSubstitution dependent_functionElimination hypothesisEquality independent_functionElimination lambdaEquality_alt productElimination independent_pairEquality extract_by_obid isectElimination inhabitedIsType applyEquality independent_isectElimination Error :memTop,  universeIsType axiomEquality functionIsTypeImplies functionIsType productIsType equalityIstype instantiate universeEquality inrFormation_alt equalityTransitivity equalitySymmetry baseClosed unionElimination equalityElimination

Latex:
\mforall{}[A:Type].  \mforall{}[B,C:A  {}\mrightarrow{}  Type].  \mforall{}[eq:EqDecider(A)].  \mforall{}[f:a:A  fp->  B[a]].  \mforall{}[g:a:A  fp->  C[a]].
    g  \msubseteq{}  f  \moplus{}  g  supposing  \mforall{}x:A.  (((\muparrow{}x  \mmember{}  dom(f))  \mwedge{}  (\muparrow{}x  \mmember{}  dom(g)))  {}\mRightarrow{}  ((B[x]  \msubseteq{}r  C[x])  c\mwedge{}  (f(x)  =  g(x))))



Date html generated: 2020_05_20-AM-09_02_43
Last ObjectModification: 2020_01_28-PM-03_39_43

Theory : finite!partial!functions


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