Nuprl Lemma : qabs-qdiv

[r:ℚ]. ∀[s:{s:ℚ| ¬(s 0 ∈ ℚ)} ].  (|(r/s)| (|r|/|s|) ∈ ℚ)


Proof




Definitions occuring in Statement :  qabs: |r| qdiv: (r/s) rationals: uall: [x:A]. B[x] not: ¬A set: {x:A| B[x]}  natural_number: $n equal: t ∈ T
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T qdiv: (r/s) not: ¬A subtype_rel: A ⊆B uiff: uiff(P;Q) and: P ∧ Q uimplies: supposing a prop: so_lambda: λ2x.t[x] so_apply: x[s] true: True squash: T guard: {T} iff: ⇐⇒ Q rev_implies:  Q implies:  Q
Lemmas referenced :  assert-qeq int-subtype-rationals assert_wf qeq_wf2 not_wf equal-wf-T-base set_wf rationals_wf qabs_wf qmul_wf qinv_wf equal_wf squash_wf true_wf qabs-qinv iff_weakening_equal qabs-qmul
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut setElimination thin rename because_Cache addLevel sqequalHypSubstitution impliesFunctionality extract_by_obid isectElimination natural_numberEquality hypothesis applyEquality sqequalRule productElimination independent_isectElimination hypothesisEquality lambdaEquality baseClosed isect_memberEquality axiomEquality dependent_set_memberEquality imageElimination equalityTransitivity equalitySymmetry imageMemberEquality independent_functionElimination

Latex:
\mforall{}[r:\mBbbQ{}].  \mforall{}[s:\{s:\mBbbQ{}|  \mneg{}(s  =  0)\}  ].    (|(r/s)|  =  (|r|/|s|))



Date html generated: 2018_05_21-PM-11_57_01
Last ObjectModification: 2017_07_26-PM-06_47_26

Theory : rationals


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