Nuprl Lemma : bag-function

∀[T,A:Type]. ∀[f:(T List) ⟶ bag(A)].
  f ∈ bag(T) ⟶ bag(A) supposing ∀as,bs:T List.  (f[as @ bs] = (f[as] + f[bs]) ∈ bag(A))


Proof




Definitions occuring in Statement :  bag-append: as + bs,  bag: bag(T),  append: as @ bs,  list: T List,  uimplies: b supposing a,  uall: ∀[x:A]. B[x],  so_apply: x[s],  all: ∀x:A. B[x],  member: t ∈ T,  function: x:A ⟶ B[x],  universe: Type,  equal: s = t ∈ T
Definitions unfolded in proof :  member: t ∈ T,  squash: ↓T,  uall: ∀[x:A]. B[x],  prop: ℙ,  so_lambda: λ2x.t[x],  so_apply: x[s],  all: ∀x:A. B[x],  true: True,  subtype_rel: A ⊆r B,  uimplies: b supposing a,  guard: {T},  iff: P ⇐⇒ Q,  and: P ∧ Q,  rev_implies: P ⇐ Q,  implies: P ⇒ Q,  append: as @ bs,  so_lambda: so_lambda(x,y,z.t[x; y; z]),  top: Top,  so_apply: x[s1;s2;s3],  bag: bag(T),  quotient: x,y:A//B[x; y],  so_lambda: λ2x y.t[x; y],  so_apply: x[s1;s2],  trans: Trans(T;x,y.E[x; y]),  refl: Refl(T;x,y.E[x; y])
Lemmas referenced :  all_wf,  squash_wf,  true_wf,  list_wf,  equal_wf,  bag_wf,  cons_wf,  nil_wf,  iff_weakening_equal,  list_ind_cons_lemma,  list_ind_nil_lemma,  permutation-invariant2,  bag-append_wf,  bag-append-assoc-comm,  equal-wf-base,  permutation_wf,  bag-append-comm,  append_wf
Rules used in proof :  cut,  applyEquality,  thin,  sqequalSubstitution,  sqequalTransitivity,  computationStep,  sqequalReflexivity,  lambdaEquality,  sqequalHypSubstitution,  imageElimination,  introduction,  extract_by_obid,  isectElimination,  hypothesisEquality,  equalityTransitivity,  hypothesis,  equalitySymmetry,  functionEquality,  cumulativity,  universeEquality,  because_Cache,  sqequalRule,  functionExtensionality,  dependent_functionElimination,  natural_numberEquality,  imageMemberEquality,  baseClosed,  independent_isectElimination,  productElimination,  independent_functionElimination,  lambdaFormation,  isect_memberEquality,  voidElimination,  voidEquality,  pointwiseFunctionalityForEquality,  pertypeElimination,  productEquality,  isect_memberFormation,  axiomEquality

Latex:
\mforall{}[T,A:Type].  \mforall{}[f:(T  List)  {}\mrightarrow{}  bag(A)].
    f  \mmember{}  bag(T)  {}\mrightarrow{}  bag(A)  supposing  \mforall{}as,bs:T  List.    (f[as  @  bs]  =  (f[as]  +  f[bs]))



Date html generated: 2017_10_01-AM-08_45_09
Last ObjectModification: 2017_07_26-PM-04_30_34

Theory : bags


Home Index