Nuprl Lemma : sum-equal-terms

∀[n:ℕ]. ∀[a:ℕn ⟶ ℤ]. ∀[m:ℕ]. ∀[b:ℕm ⟶ ℤ].
  Σ(a[i] | i < n) = Σ(b[j] | j < m) ∈ ℤ 
  supposing permutation(ℤ;filter(λx.(¬b(x =z 0));map(λi.a[i];upto(n)));filter(λx.(¬b(x =z 0));map(λj.b[j];upto(m))))


Proof




Definitions occuring in Statement :  permutation: permutation(T;L1;L2),  upto: upto(n),  sum: Σ(f[x] | x < k),  filter: filter(P;l),  map: map(f;as),  int_seg: {i..j-},  nat: ℕ,  bnot: ¬bb,  eq_int: (i =z j),  uimplies: b supposing a,  uall: ∀[x:A]. B[x],  so_apply: x[s],  lambda: λx.A[x],  function: x:A ⟶ B[x],  natural_number: $n,  int: ℤ,  equal: s = t ∈ T
Definitions unfolded in proof :  uall: ∀[x:A]. B[x],  member: t ∈ T,  uimplies: b supposing a,  squash: ↓T,  prop: ℙ,  so_lambda: λ2x.t[x],  so_apply: x[s],  true: True,  subtype_rel: A ⊆r B,  guard: {T},  iff: P ⇐⇒ Q,  and: P ∧ Q,  rev_implies: P ⇐ Q,  implies: P ⇒ Q,  nat: ℕ
Lemmas referenced :  equal_wf,  squash_wf,  true_wf,  istype-universe,  sum-l_sum,  int_seg_wf,  subtype_rel_self,  iff_weakening_equal,  l_sum_filter0,  map_wf,  upto_wf,  l_sum_wf,  l_sum_functionality_wrt_permutation,  filter_wf5,  bnot_wf,  eq_int_wf,  istype-int,  l_member_wf,  permutation_wf
Rules used in proof :  sqequalSubstitution,  sqequalTransitivity,  computationStep,  sqequalReflexivity,  isect_memberFormation_alt,  introduction,  cut,  applyEquality,  thin,  lambdaEquality_alt,  sqequalHypSubstitution,  imageElimination,  extract_by_obid,  isectElimination,  hypothesisEquality,  equalityTransitivity,  hypothesis,  equalitySymmetry,  universeIsType,  instantiate,  universeEquality,  intEquality,  sqequalRule,  because_Cache,  natural_numberEquality,  imageMemberEquality,  baseClosed,  independent_isectElimination,  productElimination,  independent_functionElimination,  setElimination,  rename,  setIsType,  isect_memberEquality_alt,  axiomEquality,  isectIsTypeImplies,  inhabitedIsType,  functionIsType

Latex:
\mforall{}[n:\mBbbN{}].  \mforall{}[a:\mBbbN{}n  {}\mrightarrow{}  \mBbbZ{}].  \mforall{}[m:\mBbbN{}].  \mforall{}[b:\mBbbN{}m  {}\mrightarrow{}  \mBbbZ{}].
    \mSigma{}(a[i]  |  i  <  n)  =  \mSigma{}(b[j]  |  j  <  m) 
    supposing  permutation(\mBbbZ{};filter(\mlambda{}x.(\mneg{}\msubb{}(x  =\msubz{}  0));map(\mlambda{}i.a[i];upto(n)));
                                                filter(\mlambda{}x.(\mneg{}\msubb{}(x  =\msubz{}  0));map(\mlambda{}j.b[j];upto(m))))



Date html generated: 2020_05_20-AM-08_15_56
Last ObjectModification: 2020_01_04-PM-11_11_57

Theory : general


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