Nuprl Lemma : ranked-eo-first

[L,rk:Top]. ∀[e:Id × ℤ].  (first(e) (snd(e) =z 0))


Proof




Definitions occuring in Statement :  ranked-eo: ranked-eo(L;rk) es-first: first(e) Id: Id eq_int: (i =z j) uall: [x:A]. B[x] top: Top pi2: snd(t) product: x:A × B[x] natural_number: $n int: sqequal: t
Lemmas :  Id_wf top_wf ranked-eo-dom ranked-eo-pred eq_int_wf bool_wf eqtt_to_assert assert_of_eq_int eqff_to_assert equal_wf bool_cases_sqequal subtype_base_sq bool_subtype_base assert-bnot neg_assert_of_eq_int ranked-eo-eq-E subtract_wf iff_imp_equal_bool bor_wf eq_id_wf assert-eq-id not-equal-2 le_antisymmetry_iff condition-implies-le add-associates minus-one-mul add-mul-special zero-mul add-zero add-swap le-add-cancel-alt or_wf member_wf equal-wf-base int_subtype_base iff_transitivity assert_wf iff_weakening_uiff assert_of_bor assert_of_band iff_wf true_wf

Latex:
\mforall{}[L,rk:Top].  \mforall{}[e:Id  \mtimes{}  \mBbbZ{}].    (first(e)  \msim{}  (snd(e)  =\msubz{}  0))



Date html generated: 2015_07_21-PM-04_44_36
Last ObjectModification: 2015_01_27-PM-04_59_29

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